(3y^-1)-(13y^-(1/2))+14=0

Solution for (3y^-1)-(13y^-(1/2))+14=0 equation:

(3y^-1)-(13y^-(1/2))+14=0

We add all the numbers together, and all the variables

(3y^-1)-(13y^-(+1/2))+14=0

We get rid of parentheses

3y^-(13y^-(+1/2))-1+14=0

We multiply all the terms by the denominator


3y^*2))-(13y^-(+1-1*2))+14*2))=0

We add all the numbers together, and all the variables

3y^*2))-(13y^-(-1))+14*2))=0

We add all the numbers together, and all the variables

3y^*2))-(13y^-(=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$